4x^-1y^3*2x^2/3y^1/3*4y

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Solution for 4x^-1y^3*2x^2/3y^1/3*4y equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*((((2*4*x^-1*x^2*y^3)/3)*y^1)/3)*y = 0

4*((((2*4*x^-1*x^2*y^3)/3)*y)/3)*y = 0

32/9*x*y^5 = 0 // : 32/9*y^5

x = 0

x in { 0}

x belongs to the empty set

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